Distribution of n things among r persons with all possible scenario

The number of ways of distributing 50 identical things among 8 persons in such a way that three of them get 8 things each,two of them get 7 things each and remaining 3 get 4 things each,is equal to

Distribution OF Alike Things or Beggar Method

Find the number of ways to distribute 15 identical things among four persons if each gets at least two things.

The number of ways to distribute m xx n different thing among n persons equally = ((mn)!)/((m!)^(n)) The numbers of ways in which a particular player holds all the aces and all of them equal number is

The number of ways to distribute m xx n different thing among n persons equally = ((mn)!)/((m!)^(n)) The number of ways in which a pack of 52 card can be distributed among 4 players in a game bridge is

The number of ways to distribute m xx n different thing among n persons equally = ((mn)!)/((m!)^(n)) The number of ways in which 12 different books can be divided equally in 3 heaps of book is

The number of ways of distributing 12 different objects among three person such that one particular person is always getting 6 objects and the remaining two persons are getting three objects each is

Statement-1: The number solutions of the equations x+y+z=15 in the set N of all natural numbers is ""^(4)C_(2) . Statement-2: The number of ways of distributing n identical items among r persons is ""^(n+r-1)C_(r-1)

The number of ways of distributing 15 things to 4 persons each receiving at least two is