[2ax+3by=(a+2b)],[3ax+2by=2a+b]

Solve the following system of equations by method of cross-multiplication: 2ax+3by=a+2b,quad 3ax+2by=2a+b

(ax)/b-(by)/a=a+b , ax-by=2ab

If 2a=b, the pair of equations ax+by=2a^(2)-3b^(2),x+2y=2a-6b possess

(ax)/(b)-(by)/(a)=a+b,ax-by=2ab

{:(x + y = a + b),(ax - by = a^(2) - b^(2)):}

Solve the following equations by Elimination method : 6(ax+by)=3a+2b 6(bx-ay)=3b-2a .

x+y=a+b,ax-by=a^(2)-b^(2)

6(ax+by)=3a+2b&6(bx-ay)=3b-2a

If the derivative of the function f(x) is every where continuous and is given by f(x)={{:(bx^(2)+ax+4,,, x ge 1), (ax^(2)+b, ,, x lt -1):}, then : a)a = 2, b = -3 b)a = 3, b = 2 c)a = -2, b = -3 d)a = -3, b= -2

Prove that |(a,b,ax+by),(b,c,bx+cy),(ax+by, bx + cy, 0)| = (b^(2)-ac)(ax^(2) + 2bxy + cy^(2)) .