If length of perpendicular drawn from origin to any normal of the ellipse `x^2/16+y^2/25=1` is `l`, then `l` cannot be

If 'd' be the length of perpendicular drawn from origin to any normal of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 then 'd' cannot exceed

If P is the length of perpendicluar drawn from the origin to any normal to the ellipse x^(2)/25+y^(2)/16=1 , then the maximum value of p is

If P is the length of perpendicluar drawn from the origin to any normal to the ellipse x^(2)/25+y^(2)/16=1 , then the maximum value of p is

If P is the length of perpendicluar drawn from the origin to any normal to the ellipse x^(2)/25+y^(2)/16=1 , then the maximum value of p is

If P is the length of perpendicluar drawn from the origin to any normal to the ellipse x^(2)/25+y^(2)/16=1 , then the maximum value of p is

Product of perpendiculars drawn from the foci upon any tangent to the ellipse 3x^(2)+4y^(2)=12 is

Show that the product of the lengths of the perpendicular segments drawn from the foci to any tangent line to the ellipse x^2/25+y^2/16=1 is equal to 16.

Angle between the tangents drawn from point (4, 5) to the ellipse x^2/16 +y^2/25 =1 is

the locus of the foot of perpendicular drawn from the centre of the ellipse x^2+3y^2=6 on any point:

the locus of the foot of perpendicular drawn from the centre of the ellipse x^2+3y^2=6 on any point: