A ball is dropped from the top of a tower. After `2 s` another ball is thrown vertically downwards with a speed of `40 m//s`. After how much time and at what distance below the top of tower the balls meet?

Explanation

To solve the problem step by step, we will analyze the motion of both balls and use the equations of motion to find the time at which they meet and the distance below the top of the tower.

### Step 1: Understand the Problem
- A ball is dropped from the top of a tower (let's call it Ball 1).
- After 2 seconds, another ball is thrown downwards with an initial speed of 40 m/s (let's call it Ball 2).
- We need to find the time after the first ball is dropped when they meet and the distance below the top of the tower at which they meet.

### Step 2: Define Variables
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