A ball is thrown vertically upward with speed `40 m//s`. Simultaneously, another ball is dropped from a height `200 m` in the same verticle line. When and where the balls meet?

Explanation

To solve the problem of when and where the two balls meet, we can break it down into a few steps:

### Step 1: Define the motion of both balls
1. **Ball A (thrown upwards)**:
- Initial velocity (u) = 40 m/s (upward)
- Acceleration (a) = -g = -9.8 m/s² (downward)
- Displacement (s) after time t:
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