Solve : `tan^(-1)2x+tan^(-1)3x=pi/4`

Explanation

To solve the equation \( \tan^{-1}(2x) + \tan^{-1}(3x) = \frac{\pi}{4} \), we can follow these steps:

### Step 1: Use the tangent function
Since \( \tan^{-1}(a) + \tan^{-1}(b) = \tan^{-1}\left(\frac{a+b}{1-ab}\right) \) when \( ab < 1 \), we can apply the tangent function to both sides:
\[ \tan\left(\tan^{-1}(2x) + \tan^{-1}(3x)\right) = \tan\left(\frac{\pi}{4}\right) \]

...