A particle is thrown vertically upward with speed `45 m//s`. Find the distance covered by the particle in the `5^(th)` second of its journey.

Explanation

To find the distance covered by a particle thrown vertically upward in the 5th second of its journey, we can follow these steps:

### Step 1: Understand the motion
The particle is thrown upward with an initial speed (u) of 45 m/s. The acceleration (a) due to gravity acting downward is -10 m/s² (negative because it is in the opposite direction to the motion).

### Step 2: Calculate the time to reach the maximum height
At the maximum height, the final velocity (v) becomes 0. We can use the equation of motion:
\[ v = u + at \]
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