Consider the following a-t graph for a particle moving along the x-axis. If the initial velocity is zero, sketch the v-t graph.

Explanation

`Area(1)=20, Area(2)=-20`
`t=0, v_(t=0)=0`
`v_(t=2)-v_(t=0)=Area(1)=20 impliesv_(t=2)=20 m//s`
From `t=2` to `t=4 s` , `a =0`, velocity remains the same and hence, `v_(t=4)=20 m//s`.
`v_(t=8)-v_(t=4)=Area(2)=-20`
`v_(t=8)-20=-20 implies v_(t=8)=0`
From `t=0` to `t=2 s`, velocity increases from 0 to `20 m//s`.
From `t=2` to `t=4 s`, velocity remains constant and equal to `20 m//s`.
From `t=4` to `t=8 s`, velocity decreases from `20 m//s` to zero.