A particle is dropped from the top of a tower of height 80 m. Assuming the dropping point as the origin and the downward direction position, sketch v-t, s-t and a-t graph. `(g=10 m//s^(2))`

Explanation

To solve the problem, we need to analyze the motion of the particle dropped from the top of a tower of height 80 m. We will derive the equations for velocity (v), displacement (s), and acceleration (a) over time (t) and then sketch the corresponding graphs.

### Step 1: Determine the equations of motion

1. **Initial Conditions**:
- Initial velocity (u) = 0 m/s (since the particle is dropped)
- Height of the tower (h) = 80 m
- Acceleration due to gravity (g) = 10 m/s² (downward)
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