A body moving with a uniform acceleration crosses a distance of 15 m in the `3^(rd)` second and `23 m` in the `5^(th)` second. The displacement in `10 s` will be

Options

A. `150 m`
B. `200 m`
C. `250 m`
D. `300 m`

Answer

C

Explanation

`15=u+1/2a(2xx3-1)=u+(5a)/2 …(i)`
`23=u+1/2a(2xx5-1)=u+(9a)/2 …(ii)`
Solving (i) and (ii), `a=4 m//s^(2), u=5 m//s`
Displacement in `10 s`
`S=ut+1/2at^(2)=4xx10+1/2xx4xx10^(2)`
`=250 m`