A particle is thrown vertically upward from the ground with some velocity and it strikes the ground again in time 2 s. The maximum height achieved by the particle is : `(g=10 m//s^(2))`

Options

A. 2.50 m
B. 1.25 m
C. 6.25 m
D. 5 m

Answer

D

Explanation

`A` to `B`, then `B` to `A`, time`=2 s`
`A` to `B`, time`=1 s`
`0=u-gxx1impliesu=10 m//s`
`0=u^(2)-2gHimpliesH=u^(2)/(2g)=5 m`