The acceleration due to gravity on the planet `A` is `9` times the acceleration due to gravity on planet `B`. A man jumps to a height of `2 m` on the surface of `A`. What is the height of jump by the same person on the planet `B` ?

Options

A. 18 m
B. 6 m
C. `2/3 m`
D. `2/9 m`

Answer

A

Explanation

`g_(A)=9g_(B)`
`(H_(A))_(max)=u^(2)/(2g_(A)),(H_(B))_(max)=u^(2)/(2g_(B))`
`(H_(B))_(max)/((H_(A))_(max))=g_(A)/(g_(B))=9`
`(H_(B))_(max)=9(H_(A))_(max)=9xx2=18 m`