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A particle moves along the X-axis as x=u...

A particle moves along the X-axis as `x=u(t-2s)=at(t-2)^2`.

A

(i), (ii)

B

(i), (iii)

C

(iii),(iv)

D

(i), (iii), (iv)

Text Solution

Verified by Experts

The correct Answer is:
C
`x=u(t-2)+a(t-2)^(2)`
`v=(dx)/(dt)=u(1)+a.2(t-2)`
`a^(')=(dv)/(dt)=0+2a(1)=2a`
At `t=0`, initial velocity, `v=u-4a`
At `t=2 s, x=0`
The acceleration is `2a`.
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