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If the velocity of a particle is given b...

If the velocity of a particle is given by `v=(180-16x)^((1)/(2))(m)/(s)`, then its acceleration will be

A

Zero

B

`8 m//s^(2)`

C

`-8 m//s^(2)`

D

`4 m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`v=(180-16x)^(1//2)`
`(dv)/(dx)=1/2(180-16x)^(-1//2)(-16)`
`=-8/((180-16x)^(1//2))`
`a=v(dv)/(dx)=-8`
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