A particle move a distance `x` in time `t` according to equation `x = (t + 5)^-1`. The acceleration of particle is alphaortional to.

Options

A. `(velocity)^(2//3)`
B. `(velocity)^(3//2)`
C. `(distance)^(2)`
D. `(distance)^(-2)`

Answer

B

Explanation

`x=(t+5)^(-1)`
`v=(dx)/(dt)=(-1)(t+5)^(-2)`
`a=(dv)/(dt)=2(t+5)^(-3)`
`=2[(t+5)^(-2)]^(3//2`
`a alpha v^(3//2)`