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Incenter of a Triangle

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The incenter of the triangle formed by the axes and the line (x)/(a)+(y)/(b)=1

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For triangle ABC,R=(5)/(2) and r=1. Let I be the incenter of the triangle and D,E and F be the feet of the perpendiculars from I rarr BC,CA and AB, respectively. The value of (IDxIExIF)/(IAxIBxIC) is equal to (a) (5)/(2) (b) (5)/(4)(c)10(d)(1)/(5)

On the Argand plane z_(1),z_(2) and z_(3) are respectively,the vertices of an isosceles triangle ABC with AC=BC and equal angles are theta. If z_(4) is the incenter of the triangle,then prove that (z_(2)-z_(1))(z_(3)-z_(1))=(1+sec theta)(z_(4)-z_(1))^(2)

The incenter of the triangle with vertices (1,sqrt(3)),(0,0), and (2,0) is (a) (1,(sqrt(3))/(2)) (b) ((2)/(3),(1)/(sqrt(3)))(c)((2)/(3),(sqrt(3))/(2)) (d) (1,(1)/(sqrt(3)))

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