A wire is bent in the form of a regular hexagon and a total charge q is distributed uniformly on it. What is the electric field at the centre? You may answer this part without making any numerical calculations.

Options

A. `(q)/(4 pi epsilon_(0)a^(2))`
B. zero
C. `(3q)/(4 pi epsilon_(0)a^(2))`
D. `(4q)/(4 pi epsilon_(0)a^(2))`

Answer

2

Explanation

At centre electric field is zero , because facing charges produce equal and opposite electric field.