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An electron of mass m(e ) initially at r...

An electron of mass `m_(e )` initially at rest moves through a certain distance in a uniform electric field in time `t_(1)`. A proton of mass `m_(p)` also initially at rest takes time `t_(2)` to move through an equal distance in this uniform electric field.Neglecting the effect of gravity, the ratio of `t_(2)//t_(1)` is nearly equal to

A

`1`

B

`sqrt((m_(e ))/(m_(p)))`

C

`sqrt((m_(p))/(m_(e)))`

D

`1836`

Text Solution

Verified by Experts

The correct Answer is:
3

`s = (1)/(2) a_(1) t_(1)^(2) = (1)/(2) a_(2) t_(2)^(2)`
`(t_(2))/(t_(1)) = sqrt((a_(1))/(a_(2))) = sqrt((eE//m_(e))/(eE//m_(p))) = sqrt((m_(p))/(m_(e ))`
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