A deuteron and an `alpha`-particle are placed in an electric field.The forces acting on them are `F_(1)` and `F_(2)` and their accelerations are `a_(1)` and `a_(2)` respectively.
(i) `F_(1) = F_(2)`
(ii) `F_(1) != F_(2)`
(iii) `a_(1) = a_(2)`
(iv) `a_(1) != a_(2)`

Options

A. `(i),(ii)`
B. `(ii),(iii)`
C. `(ii),(iv)`
D. `(i),(iv)`

Answer

2

Explanation

Deutron `(e,2m) , alpha`-particle `(2e , 4m)`
`F_(1) = eE , F_(2) = 2eE`
`a_(1) = (eE)/(2m) ,a_(2) = (2eE)/(4m) = (eE)/(2m)`
`F_(1) != F_(2) ,a_(1) = a_(2)`