A simple pendulum has a length `l`, mass of bob `m`. The bob is given a charge `q`.The pendulum is suspended between the vertical plates of charged parallel plate capacitor. If `E` is the field strength between the plates ,then time period `T = `

Options

A. `2 pi sqrt((l)/(g))`
B. `2 pi sqrt({(l)/(g + (qE)/(m))})`
C. `2 pi sqrt({(l)/(g - (qE)/(m))})`
D. `2 pi sqrt((l)/((g^(2) + ((qE)/(m))^(2))^(1//2)))`

Answer

4

Explanation

`a = sqrt((qE)^(2) + (mg)^(2))/(m) = sqrt(g^(2) + ((qE)/(m))^(2))`