A bullet of mass `2 gm` is having a charge of `2 muc`. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of `10 m//s`

Options

A. `5 kV`
B. `50 kV`
C. `5 V`
D. `50 V`

Answer

2

Explanation

`K = qV`
`(1)/(2) mv^(2) = qV`
`V = (mv^(2))/(2q) = (2 xx 10^(-3) xx (10)^(2))/(2 xx 2 xx 10^(-6))`
`= 5 xx 10^(4) V`
`= 50 kV`