" (b) In the matrix "A=|[a,1,x],[2,sqrt(3),x^(2)-y],[0,5,(-2)/(5)]|" write "

In the matrix A=[{:(a,1,x),(2,sqrt(3),x^(2)-y) ,(0,5,(-2)/(5)):}] write (i) the order of the matrix A. (ii) the number of elements. (iii) elements a_(23) ,a_(31) and a_(1) ,

In the matrix A=[{:(a,1,x),(2,sqrt(3),x^(2)-y) ,(0,5,(-2)/(5)):}] write (i) the order of the matrix A. (ii) the number of elements. (iii) elements a_(23) ,a_(31) and a_(1) ,

In the matrix A=[{:(a,1,x),(2,sqrt(3),x^(2)-y),(0,5,-(2)/(5)):}] , write : (i) The order of the matrix A (ii) The number of elements (iii) Write elements a_(23),a_(31),a_(12)

In the matrix A=[{:(a,1,x),(2,sqrt(3),x^(2)-y),(0,5,-2//5):}] Write (i) the order of the matrix A. (ii) the number of elements. (iii) the value of elements a_(23),a_(31) and a_(12) .

Find x and y satisfying the matrix equation [(x-y,2,-2),(4,x,6)] + [(3,-2,2),(1,0,-1)] = [(6,0,0),(5,2x+y,5)]

Find a matrix X such that 2A + B + X = 0 where A={:[(-1,2),(3,4)],B={:[(3,-2),(1,5)]:}

The range of parameter ' a ' for which the variable line y=2x+a lies between the circles x^2+y^2-2x-2y+1=0 and x^2+y^2-16 x-2y+61=0 without intersecting or touching either circle is (a) a in (2sqrt(5)-15 ,0) (b) a in (-oo, 2sqrt(5)-15,) (c) a in (2sqrt(5)-15,-sqrt(5)-1) (d) a in (-sqrt(5)-1,oo)

The range of parameter ' a ' for which the variable line y=2x+a lies between the circles x^2+y^2-2x-2y+1=0 and x^2+y^2-16 x-2y+61=0 without intersecting or touching either circle is (a) a in (2sqrt(5)-15 ,0) (b) a in (-oo, 2sqrt(5)-15,) (c) a in (2sqrt(5)-15,-sqrt(5)-1) (d) a in (-sqrt(5)-1,oo)

Domain of the explicit from of the function y represented implicity by the equation (1+x)cos y-x^(2)=0 is-a.(-1,1]b(-1,(1-sqrt(5))/(2)]c*[(1-sqrt(5))/(2),(1+sqrt(5))/(2)]d[0,(1+sqrt(5))/(2)]

The coordinates (2,3) and (1,5) are the foci of an ellipse which passes through the origin. Then the equation of the (a)tangent at the origin is (3sqrt(2)-5)x+(1-2sqrt(2))y=0 (b) tangent at the origin is (3sqrt(2)+5)x+(1+2sqrt(2)y)=0 (c)tangent at the origin is (3sqrt(2)+5)x-(2sqrt(2+1))y=0 (d) tangent at the origin is (3sqrt(2)-5)-y(1-2sqrt(2))=0