A point charge q is placed at a distance...

A point charge `q` is placed at a distance `a//2` directly above the centre of a square of side `a`. The electric flux through the square is

`(q)/(pi epsilon_(0))`

`(q)/(6 epsilon_(0))`

`(q)/(epsilon_(0))`

zero

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Verified by Experts

The correct Answer is:

Complete the cube in such a manner so that charge `+q`is at centre
Flux through cube `= q//in_(0)`
By symmetry ,flux through one face `= (q)/(6 in_(0))`

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