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Charges Q1 and Q2 lie inside and outside...

Charges `Q_1 and Q_2` lie inside and outside, respectively, of a closed surface S. Let E be the field at any point on S and `phi` be the flux of E over S.

A

If `O_(1)` changes , both `E` and `phi` will change

B

If `Q_(2)` changes , `E` will change but `phi` will not change

C

If `Q_(1) = 0` and `Q_(2) !=0` then `E = 0` but `phi != 0`

D

If `Q_(1) ne 0` and `Q_(2) ne 0` then `E = 0` ut `phi ne 0`

Text Solution

Verified by Experts

The correct Answer is:
4


`phi = oint vec(E ) . vec(dS) = (Q_(1))/(in_(0))`
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