Some equipotential surfaces are shown in figure . The magnitude and direction of electric field is

Options

A. `2 V//cm` at angle `120^(@)` with `+ve` x-axis in anticlockwise direction
B. `2 V//cm` at angle `120^(@)` with `+ve` x-axis in clockwise direction
C. `1 V//cm` at angle `150^(@)` with `+ve` x-axis in anticlockwise direction
D. `1 V//cm` at an angle `120^(@)` with `+ve` x-axis in clockwise direction

Answer

1

Explanation

Electric field `= (Delta V)/(_|_^(ar) "distance b/w equipotential lines")`
`E = (20 - 10)/(10 sin 30^(@)) = 2 V//cm`
Uniform electric field is `_|_^(ar)` to equipotential lines and in the direction of field , potential decreases.