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An electron beam has an aperture 2 mm^2....

An electron beam has an aperture `2 mm^2`. A total of `5 xx 10^18` electrons go through any perpendicular cross-section per second. Find
(a) the current and
(b) the current density in the beam.

Text Solution

Verified by Experts

(a) `i = (q)/(t) =(n e)/(t) = (5 xx 10^18 xx 1.6 xx 10^-19)/(1) = 0.8 A`
(b) `j = (i)/(A) = (0.8)/(2 xx 10^-6) = 4 xx 10^5 A//m^2`.
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