A potential difference `50 V` is applied between the ends of conductor of length `100 m` and resistance `0.5 Omega`. The conductor has a uniform cross-section. Find the total linear momentum of free electrons.

Explanation

`V = i R`
`50 = i xx 0.5 rArr i = 100 A`
`i= "ne" Av_d`
Momentum of one electron `= mv_d`
Total number of electron `= n A l`
Total momentum
`P = (nAl)(mv_d) = (nAv_d)(ml)`
=`(iml)/(e )`
=`(100 xx 9.1 xx 10^-31 xx 100)/(1.6 xx 10^-19) = (91)/(16) xx 10^-8`
=`5.6 xx 10^-8 kg m//sec`.