(a) Find current through each resistance.
,
(b) Find current flowing in branch `AB`

( c) Find current in `4 Omega` resistance.

(d) Find `i_0, i_1` and `V_X - V_Y`.
.

Explanation

(a) `i_1 = (60)/(6) = 10 A, i_2 = (60)/(3) = 20 A`
`i_3 = (60)/(12) = 5 A, i_4 = (60)/(60) = 1 A`
(a)
(b) ,
( c)
(d)
`i = (4)/(16) = (1)/(4) A`
`i_(0) = (24)/(5 + 1) = 4 A`
p.d. across `1 Omega = 4 xx 1 = 4 V`
`V_(x) - V_(y) = 4 V`