In the circuit shown in figure the current through

Options

A. the `3 Omega` resistor is `0.50 A`
B. the `3 Omega` resistor is `0.25 A`
C. the `4 Omega` resistor is `0.50 A`
D. the `4 Omega` resistor is `0.25 A`

Answer

D

Explanation

`R_(eq) = 9 Omega, i= (9)/(9) = 1 A`
`i_1 = i_2 = (1)/(2) A`
`i_3 = i_4 = (1)/(4) A`
Current in `4 Omega : (1)/(4) A = 0.25 A`.