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A cell drives a current through a circui...

A cell drives a current through a circuit. The emf of the cell of equal to the work done in moving unit charge (Choose the incorrect option)

A

from the positive to the negative plate of the cell

B

from the positive plate, back to the positive plate

C

from the negative plate, back to the negative plate, back to the negative plate

D

from any point in the circuit back to the same point.

Text Solution

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The correct Answer is:
A
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CP SINGH-CURRENT ELECTRICITY-Exercise
  1. In the given curcuit, the potential of the point E is

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  2. In an electric circuit containing a battery,the charge (assumed positi...

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  3. A cell drives a current through a circuit. The emf of the cell of equa...

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  4. Consider the following two statements: (A)Kirchhoff's junction law f...

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  5. Kirchoff's two law for electrical circuits are manifestations of the c...

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  6. the nonideal batteries are connected in series. Consider the following...

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  7. Two nonideal batteries are connected in parallel. Consider the followi...

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  8. The emf of a cell is epsilon and its internal resistance is r. its ter...

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  9. For a cell, a graph is plotted between the potential difference V acro...

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  10. A student measures the terminal potential difference (V) of a cell (of...

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  11. A galvanometer, together with an unknown resistance in series, is conn...

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  12. Two cells, having the same emf, are connected in series through an ext...

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  13. The n rows each containinig m cells in series are joined parallel. Max...

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  14. N identical cells, each emf E and internal resistance r are joined in ...

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  15. n identical cells, each of emf E and internal resistance r, are joined...

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  16. n identical cells, each of emf epsilon and internal resistance r, are ...

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  17. In the previous question, the potential difference across A is.

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  18. In the circuit shown below, each battery is 5V and has an internal res...

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  19. (i) i= 0.25 A (ii) VA - VB = 3.5 V (iii) VA - VC = 2.25 V Equiva...

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  20. VA - VB = ? .

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