When some potential differece is maintained between A and B, current I enters the network at A and leaves at B

Options

A. (i),(ii),(iii)
B. (ii),(iii),(iv)
C. (i),(ii),(iv)
D. (i),(iii),(iv)

Answer

C

Explanation

`C` and `D` are at same potential

`R_(eq) = 8 Omega`
`I_1 = (5)/(5 + 20) I = (I)/(5)`
`i_1 = (20)/(5 + 20) I = (4 I)/(5)`

`(I)/(5) + i = (4 I)/(5) rArr i = (3 I)/(5)`, from `D` to `C`.