In the circuit shown in the figure, if potentail at point `A` is taken to be zero, the potential at point `B` is

Options

A. `- 2 V`
B. `+ 1 V`
C. `- 1 V`
D. `+ 2 V`

Answer

C

Explanation

`i+ 1 = 2 rArr i= 1 A`
B to A (path BDCA) :
`V_B + 2 - ixx 2 + 1 = V_A`
`V_B + 2- 1 xx 2 + 1 = 0`
`V_B = 1 V`.