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Two resistance R(1) and R(2) are joined ...

Two resistance `R_(1)` and `R_(2)` are joined as shown in figure to two batteries of emf `E_(1)` and `E_(2)`. If `E_(2)` is short circuited, what is the current through `R_(1)` ?

A

`E_1//R_1`

B

`E_2//R_1`

C

`E_1//R_2`

D

`E_1//(R_2 + R_1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Short-circuit i.e. replace `E_2` by a wire

`i= E_1//R_1`.
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