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Three ammeters A,B, and C of resistances...

Three ammeters `A,B`, and `C` of resistances `R_A,R_b` and `R_C` respectively are joined as shown. When some potential difference is appllied across the terminals `T_1` and `T_2` their readings are `I_A,I_B and I_C` respectively Then,

A

`I_A = I_B`

B

`I_A R_A + I_B R_B = I_C R_C`

C

`(I_A)/(I_C) = (R_C)/(R_A)`

D

`(I_B)/(I_C) = (R_C)/(R_A + R_B)`

Text Solution

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The correct Answer is:
C
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