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Three resistance P, Q, R each of 2 Omega...

Three resistance `P, Q, R` each of `2 Omega` and an unknown resistance `S` from the four amrs of a Wheatstone's bridge circuit. When a resistance of `6 Omega` is connected in parallel to `S` the bridge gets balanced. What is the value of `S` ?

A

`2 Omega`

B

`3 Omega`

C

`6 Omega`

D

`1 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B

`(2)/(2) = (2)/(6 S//(S + 6))`
`3 S = S + 6 rArr S = 3 Omega`.
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