(i)The radical axis is perpendicular to the line joining the centres of the given circles.

ln n(n>=3) circles the centres of no three circles are collinear. If the number of the radical axes of the circles is equal to the number of the radical centres of the circles then n^(2)-4n-5=

Three circle of radius 6 cm touches each other externally. Then the distance of the centre of one circle from the line joining the centres of other two circles is equal to

The radical axis of two touching circles divides the line segment joining the centre of circles in the ratio of their

A circle touches a given straight line and cuts off a constant length 2d from another straight line perpendicular to the first straight line. The locus of the centre of the circle, is

The moment of inertia of HCl molecule about an axis passing through its centre of mass and perpendicular to the line joining the H^+ and Cl^- ions will be (if the inter atomic distance is 1A^@ )

(iii)If two circles cut a third circle orthogonally,then the radical axis of two circle will pass through the center of the third circle.

Show that the magnetic field at a point due to a magnetic dipole is perpendicular to the magnetic axis if the line joining the point with the centre of the dipole makes an angle of tan^(-1) (sqrt(2)) with the magnetic axis.