Home
Class 12
PHYSICS
Light enters from vacuum to a medium of ...

Light enters from vacuum to a medium of refractive index `mu`. If angle of incidence is double of angle of refraction, find angle of refraction.

Text Solution

Verified by Experts


`i=2theta`, `r=theta`
`mu_1sini=mu_2sinr`
`1xxsin2theta=musintheta`
`2 sin theta cos theta=mu sin theta`
`costheta=mu/2`
`theta=cos^-1(mu/2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • REFRACTION OF LIGHT BY PLANE SURFACES

    CP SINGH|Exercise Exercises|110 Videos

  • REFRACTION AT SPHERICAL SURFACES

    CP SINGH|Exercise EXERCISES|105 Videos

  • SEMICONDUCTORS

    CP SINGH|Exercise Exercises|140 Videos

Similar Questions

Explore conceptually related problems

Give a formula to find refractive index of a glass slab in terms of angle of incidence and angle of refraction.

The ray of light travels from raer medium to denser medium of refractive index mu . The angle of incidence of twice the angle of refraction. The angle of incidence is given by

Knowledge Check

  • A ray of light passes from vacuum into a medium of refractive index n . If the angle of incidence is twice the angle of refraction , then the relation between the angle of incidence and the refractive index is

    A
    `n = 2 sin ((i)/(2))`
    B
    `n = 2 cos ((i)/(2))`
    C
    ` n = 2 tan ((i)/(2))`
    D
    `n = (1)/(2) [ cos ((i)/(2))]`

  • A ray of light passes from vaccum into a medium of refractive index n. If the angle of incidence is twice the angle of refraction, then the angle of incidence is

    A
    `cos^-1(n//2)`
    B
    `sin^-1(n//2)`
    C
    `2cos^-1(n//2)`
    D
    `2 sin^-1(n//2)`

  • A ray of light passes from vaccume into a medium of refractive index n. if the angle of incidence is twice the angle of refraction, then the angle of incidence is

    A
    `cos^(-1)(n//2)`
    B
    `sin^(-1)(n//2)`
    C
    `2 cos^(-1)(n//2)`
    D
    `2sin^(-1)(n//2)`

    • Similar Questions

    Explore conceptually related problems

    A ray of light passes from vacuum of 3xx10^8 m//s medium of refractive index mu , the angle of incidence is found to be twice the angle of refraction. Then the angle of incidence is:

    A ray of light passes from vacuum of 3xx10^8 m//s medium of refractive index mu , the angle of incidence is found to be twice the angle of refraction. Then the angle of incidence is:

    A ray of light travels from a medium of refractive index n_(1) to a medium of refractive index n_(2) . If angle of incidence is i and angle of refraction is r, than (sin i)/(sin r) is equal to

    A ray of light goes from a medium of refractive index n_1 to a medium of refractive index n_2 . The angle of incidence is I and the angle of refraction is r. Then, sin i/sin r is equal to

    A ray of light passes from free space to a medium of refractive index 1.6. If the angle of refraction is half the angle of incidence, the angle of incidence is equal to

    Home
    Profile