A light ray is incident at an angle of `45^@` with the normal to a `2cm` thick plate `(mu=2.0)`. Find the shift in the path of the light as it emerges out from the plate.

Explanation

Lateral shift
`BC=(tsin(i-r))/(cosr)`
`=tsini[1-(cosi)/(sqrt(mu^2-sin^2i))]`
`=2sin45^@[1-(cos45^@)/(sqrt((2)^2-(sin^2 45^@)))]`
`=(2)/(sqrt2)[1-(1//sqrt2)/(sqrt(4-1//2))]=sqrt2(1-1/sqrt7)`