Home
Class 12
PHYSICS
(i) mu=(c)/(vm)=(vlambda)/(vlambdam) w...

(i) `mu=(c)/(v_m)=(vlambda)/(vlambda_m)`
where
c: speed of light in vacuum
`v_m:` speed of light in medium
`lambda:` wavelength in vacuum
`lambda_m`: wavelength in medium
`upsilon:` frequency of light
(ii) `mu=((epsilonmu)/(epsilon_0mu_0))^(1/2)`
where `epsilon:` electric permittivity in free space
`epsilon:` electric permittivity in medium
`mu_0:` magnetic permeability in free space
`mu:` magnetic permeability in medium
(iii) `mu=A+B/lambda^2`, where A and B are constants
(iv) In case of VIBGYOR, wavelength increases from violet to red, refractive index decreases from violet to red. Wavelength for red-colour is maximum whereas refractive index is maximum for violet colour.

A

(i), (ii)

B

(ii), (iii)

C

(ii), (iii), (iv)

D

all options are correct

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • REFRACTION OF LIGHT BY PLANE SURFACES

    CP SINGH|Exercise Exercises|110 Videos

  • REFRACTION AT SPHERICAL SURFACES

    CP SINGH|Exercise EXERCISES|105 Videos

  • SEMICONDUCTORS

    CP SINGH|Exercise Exercises|140 Videos

Similar Questions

Explore conceptually related problems

Write expression for speed of em waves in a medium of electrical permittivity in and magnetic permeability mu

What are the dimensions of mu_(0)epsilon_(0) ? Here mu_(0)= magnetic permeability in vacuum, epsilon_(0)= electric permittivity in vacuum

Knowledge Check

  • Find the dimension of epsilon_(0)E^(2) , where epsilon_(0) is permittivity of free space and E is the electricity field

    A
    `[M^(1) L^(1) T^(-2) A^(1)]`
    B
    `[M^(1) L^(0)T^(-1)]`
    C
    `[M^(1) L^(-1) T^(-2) A^(1)]`
    D
    `[M^(1) L^(-1) T^(-2)]`

  • SI unit of magnetic permeability mu_0 (" or " mu) is

    A
    `A m^(-1)`
    B
    `T m A^(-1)`
    C
    `T m`
    D
    `A m^2`

  • The dimension of ((1)/(2))epsilon_(0)E^(2) ( epsilon_(0) : permittivity of free space, E electric field

    A
    (a) `MLT^(-1)`
    B
    (b) `ML^(2)T^(2)`
    C
    ( c ) `ML^(-1)T^(-2)`
    D
    ( d ) `ML^(2)T^(-1)`

    • Similar Questions

    Explore conceptually related problems

    A physical relation is epsilon=epsilon_(0)epsilon_(r) where epsilon= electric permittivity of a medium epsilon_(0)= electric permittivity of vacuum epsilon_(r)= relative permittivity of medium What are dimensions of relative permittivity?

    Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

    If V_(c) is the speed of light in vacuum and V_(m) is the speed of light in given medium then the refractive index of medium is

    If the wavelength of light in vacuum be lambda , the wavelength in a medium of refractive index n will be

    The dimensions of 1/2 epsilon_(0)E^(2) (epsilon_(0)= permittivity of free space, E= electric field) is

    Home
    Profile