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A slab of glass of refractive index 1.5 ...

A slab of glass of refractive index `1.5` and thickness `3cm` is placed with the faces perpendicular to the principle axis of a concave mirror. If the radius of curvature of the mirror is `10cm`, the distance at which an object must be placed from the mirror so that the image coincides with the object is

A

`9cm`

B

`10cm`

C

`11cm`

D

`12cm`

Text Solution

Verified by Experts

The correct Answer is:
C


Shift of mirror towards object `=3(1-(1)/(3//2))=1cm`
If object and image coincides, for this object must be placed at centre of curvature of concave mirror i.e. at distance `10cm P^'`.
The distance O from actual mirror i.e. `PO=11cm`
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