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A light beam is travelling from Region I...

A light beam is travelling from Region `I` to `IV` (figure). The refractive index in regionals `I,II,III` and `IV` are `n_0=(n_0)/(2)`(n_0)/(6) and (n_0)/(8)` respectively. The angle of incidence `theta` for which the beam just misses entering region IV is- `

A

`sin^-1(3/4)`

B

`sin^-1(1/8)`

C

`sin^-1(1/4)`

D

`sin^-1(1/3)`

Text Solution

Verified by Experts

The correct Answer is:
B
`n_0sintheta=n_0/8sin90^@`
`theta=sin^-1(1//8)`
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