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A prism of angle 60^@ deviates a ray of ...

A prism of angle `60^@` deviates a ray of light through `32^@` for two angles of incidence which differ by `12^@`. The angles of incidence are

A

`46^@`, `58^@`

B

`36^@`, `48^@`

C

`50^@`, `38^@`

D

`52^@`, `40^@`

Text Solution

Verified by Experts

The correct Answer is:
D
`delta=(i+i^')-A`
`32^@=(i+i^')-60^@impliesi+i^'=92^@` …(i)
`i-i^'=12^@` …(ii)
Solving, `i=52^@`, `i^'=40^@`
Note: Angle of deviation will be same for two angles `i` and `i^'`.
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