In a compound microscope, the objects is `1cm` form the objective lens. The lenses are `30cm` apart and the intermediate image is `5cm` from the eye-piece. What magnification is produced?

Explanation

`u_(0) =- 1cm, L = 30 cm, u_(e) =- 5 cm`
For normal adjustment
`f_(e) = |u_(e)| = 5 cm`
`L = v_(0) +f_(e) rArr 30 = v_(0) +5 rArr v_(0) = 25 cm`
`m = (v_(0))/(u_(0))(D)/(f_(e))`
`= (25)/(-1) xx (25)/(5)`
`=- 125`