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Wavelength of light used in an optical i...

Wavelength of light used in an optical instrument are `lambda_(1) = 4000 Å` and `lambda_(2) = 5000Å` then ratio of their respective resolving powers (corresponding to `lambda_(1)` and `lambda_(2)`) is

A

`16 : 25`

B

`9 : 1`

C

`4 : 5`

D

`5 : 4`

Text Solution

Verified by Experts

The correct Answer is:
D
`R.P = (a)/(1.22lambda)`
`R.P. prop (1)/(lambda)`
`((R.P.)_(1))/((R.P.)_(2)) = (lambda_(2))/(lambda_(1)) = (5000)/(4000) = (5)/(4)`
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