In a YDSE, the separation between slits is `2 mm` where as the distance of screen from the plane of slits is `2.5 m`. Light of wavelengths in the range `200-800 nm` is allowed to fall on the slits. Find the wavelengths in the visible region that will be present on the screen at `1 mm` from central maximum. Also find the wavelength that will be present at that point of screen in the infrared as well as in the ultraviolet region.

Explanation

To solve the problem step by step, we will use the formula for the position of bright fringes in Young's Double Slit Experiment (YDSE):

### Step 1: Identify the given values
- Distance between slits (D) = 2 mm = \(2 \times 10^{-3}\) m
- Distance from slits to screen (L) = 2.5 m
- Distance from the central maximum to the point of interest on the screen (X) = 1 mm = \(1 \times 10^{-3}\) m
- Wavelength range = 200 nm to 800 nm = \(200 \times 10^{-9}\) m to \(800 \times 10^{-9}\) m

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