In Young's experiment, the distance between the slits is 0.025 cm and the distance of the screen from the slits is 100 cm. If two distance between their second maxima in cm is

Options

A. 0.048
B. 0.096
C. 0.12
D. 0.192

Answer

B

Explanation

`d=0.025 cm, D=1m, lambda_(1)=440 nm, lambda_(2)=560 nm`
`y_(2)=(2Dlambda_(1))/d, y_(2)^(')=(2Dlambda_(2))/d`
`y_(2)^(')-y_(2)=(2D)/d(lambda_(2)-lambda_(1))`
`=(2xx1)/(0.025xx10^(-2))(560-440)xx10^(-9)`
`=0.096 cm`