In Young's double-slit experiment using `lambda=6000 Å`, distance between the screen and the source is 1m. If the fringe-width on the screen is 0.06 cm, the distance between the two coherent sources is

Options

A. `0.01 mm`
B. `1 cm`
C. `0.01 mm`
D. `1 mm`

Answer

D

Explanation

`lambda=6000Å=6xx10^(-7)m, D=1m`,
`beta=0.06 cm=6xx10^(-4)m`
`beta=(Dlambda)/d`
`6xx10^(-4)=(1xx6xx10^(-7))/d implies d=10^(-3)m=1 mm`