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In a Young's double-slit experiment, let...

In a Young's double-slit experiment, let `S_(1)` and `S_(2)` be the two slits, and `C` be the centre of the screen. If `/_S_(1)CS_(2)=theta` and `lambda` is wavelength, the fringe width will be

A

`lambda/theta`

B

`lambda theta`

C

`(2lambda)/theta`

D

`lambda/(2theta)`

Text Solution

Verified by Experts

The correct Answer is:
A


`theta=d/D`
`beta=(Dlambda)/d=lambda/theta`
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