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A ray of light intensity I is incident o...

A ray of light intensity I is incident on a parallel glass-slab at a point `A` as shown in figure. It undergoes partial reflection and refraction. At each reflection `25%` of incident energy is reflected. The rays `AB` and `A^(')B^(')` undergo interference. The ratio `I_(max)//I_(min)` is

A

`4:1`

B

`8:1`

C

`7:1`

D

`49:1`

Text Solution

Verified by Experts

The correct Answer is:
D

`I_(1)=I//4, I_(2)=9I//64`
`I_(max)/I_(min)=((sqrt(I_(1))+sqrt(I_(2)))/(sqrt(I_(1))~sqrt(I_(2))))^(2)=((sqrt(I//4)+sqrt(9I//64))/(sqrt(I//4)-sqrt(9I//64)))^(2)`
`=((1/2+3/8)/(1/2-3/8))^(2)=(7/1)^(2)=49/1`
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Knowledge Check

  • A ray of light of intensity I is incident on a parallel glass slab at point A as shown in diagram. It undergoes partial reflection and refraction. At each reflection, 25% of incident energy is reflected. The rays AB and A'B' undergo interference. The ratio of I_("max") and I_("min") is :

    A
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    B
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    C
    `4:1`
    D
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    A
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    B
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