In a YDSE with identical slits, the intensity of the central bright fringe is `I_(0)`. If one of the slits is covered, the intensity at the same point is

Options

A. `I_(0)`
B. `I_(0)//2`
C. `I_(0)/4`
D. `I_(0)/(2sqrt(2)`

Answer

C

Explanation

`I_(1)=I_(2)=I^(')`
`I=4I^(') cos_(2)(phi//2)`
`phi=0, I_(0)=4I^(') implies I^(')=I_(0)//4`
When one slit is covered, no interference,
Resultant intensity `=I^(')=I_(0)//4`